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11Alexandr11 [23.1K]
3 years ago
15

Write the number in two other forms 15,409

Mathematics
1 answer:
Katen [24]3 years ago
8 0
There are several other was to write this number:

In words: Fifteen Thousand, Four Hundred and Nine.
In scientific notation: 1.54\times10^{4}
In binary: 0b<span>11110000110001
In hexadecimal: 0x</span><span>3C31</span><span>
In prime factorization:
15,409=19\times811




</span>
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I need help with this please asap
Alex

Step-by-step explanation:

We can prove that the triangles are congruent using the SAS method.

It's given that GH and JH are congruent (S)

Angle GHF and Angle IHJ are equal since they are vertically opposite (A)

It's given that FH and HI are congruent (S)

Thus, the triangles are congruent, which implies that the remaining sides are equal.

6 0
3 years ago
Please help me. This is timed. Will mark BRAINLIEST.
Vitek1552 [10]

Answer:

Solution (1.8,1.61)

Step-by-step explanation:

Let us do it one by one.

Graph 1 :

y=-3x+7

Let us find some random coordinates to graph this equation

x = 0 ; y = -3(0)+7 = 7  

(0,7)

x=1 ; y=-3(1) + 7 = -3+7=4

(1,4)

Plotting these coordinates on graph , and joining them will give us the line on the graph.

Graph 2 :

y = Sqrt ( 2x-1)

let us find random cordinates for some values of x

x=1, y = sqrt (2(1)-1) = sqrt (1) = 1

(1,1)

x=0.5 , y = sqrt (2(0.5)-1) = sqrt (0) = 0

(0.5,0)

Hence we have two coordinates , now we also see that , after comparing it from standard form of an square root function,

the square root function is upper half of parabola opening towards right and the point of origin is (0.5,0)

Let us find the solution , for that we need to put y=-3x+7 in y=sqrt (2x-1)

and we get

-3x+7=sqrt (2x-1)

squaring on both sides we get

9x^2+49-42x=2x-1

9x^2-44x+50=0

solving it with quadratic formula

x=[-b+sqrt(b^2-4ac)]/2a

we get x  = 1.8 and replacing it in first equation we get y = 1.61

Hence the solution will be (1.8,1.61)

7 0
3 years ago
The multiplication property of equality could be used to solve which of the following equations?
MArishka [77]
The third one; b÷(-2)=18
7 0
3 years ago
Read 2 more answers
Find the indicated limit, if it exists.
jok3333 [9.3K]
For the limit to exist, the limits from either side must also exist and be identical. We have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1

Since the limits do not match, the overall limit does not exist.
6 0
3 years ago
Is it that true ⅖-¾=¼+2/5
harkovskaia [24]
No, 2/5-3/4 is -7/20 and 1/4+2/5 is 13/20 they do not equal the same the so the answer is no because it’s not true
6 0
3 years ago
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