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alexandr402 [8]
3 years ago
10

Find the indicated limit, if it exists.

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0
For the limit to exist, the limits from either side must also exist and be identical. We have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1

Since the limits do not match, the overall limit does not exist.
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Makaila read 44 pages of her book yesterday and 2/3 of the book today. If she read a total of 200 pages in the past two days how
pogonyaev

Answer:

Total number of pages in the book is 234.

Step-by-step explanation:

Let us assume that the total number of pages in the book = <em>x</em>

Now, it is given that Makaila read 44 pages yesterday.

Also, Makaila read two-third of the book today. As we have assumed that, there are a total of x number of pages in the book, so we can say that Makaila read two-third of <em>x </em>number of pages today.

Number of pages read by Makaila today = \frac{2}{3}\;of\;x=\frac{2}{3}\times\;x=\frac{2x}{3}

Now, it is also given that, Makaila read a total of 200 pages in the past two days.

∴ according to question,

Pages read yesterday + Pages read today = 200

⇒44+\frac{22x}{3}=200

⇒\frac{44\times3+2x}{3}=200

⇒\frac{132+2x}{3}=200

⇒132+2x=200\times3\;\;\;\;\;\;\;\;\;[On\;cross-multiplying]

⇒132+2x=600

⇒2x=600-132

⇒2x=468

⇒x=\frac{468}{2}=234

∴ Total number of pages in the book = <em>x</em> = 234

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Step-by-step explanation

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Answer:

\large\boxed{\dfrac{3(6)-1}{2(6)+1}}

Step-by-step explanation:

\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\text{We have}\\\\f(x)=3x-1,\ g(x)=2x+1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x-1}{2x+1}\\\\\left(\dfrac{f}{g}\right)(6)\to\text{put x = 6 to the equation of the function}\ \left(\dfrac{f}{g}\right)(x):\\\\\left(\dfrac{f}{g}\right)(6)=\dfrac{3(6)-1}{2(6)+1}

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B and C are correct because you do basic PEMDAS and get 58 for both those expressions. If this is right could you possibly give me brainliest? Hope this helped.

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