Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
<span>Your Answer: D
Why....
You can make equations out of the information
Let L be Lin, G be Greg, and F be Fran
L = 4 + G ---"Lin sold 4 more shirts than Greg"
F = 3L ---"Fran sold 3 times as many shirts as Lin"
F + G + L = 51 ---"In total the three sold 51 shirts"
Use F + G + L = 51
Substitute the equations in for F and L (because you need to know the G) like this....
(3L) + G + (4+G) = 51
You still have a variable besides G in there... you can use the L= 4+G and substitute again so that there are only G's
( 3(4+G) ) + G + (4+G) = 51 ---- SIMPLIFY :D
( 12 + 3G ) + G + 4 + G = 51
12 + 3G + G + 4 + G = 51 ---Combine like terms
16 + 5G = 51 </span>
Answer:
y=(x+5)(x+2)
Step-by-step explanation:
Intercept form of quatratics is the best way to solve this equation, since you're given the roots needed.
The intercept form equation is y=a(x-p) (x-q) [where p and q are your roots/intercepts].
So, you input the intercepts and get y=(x-(-5))(x-(-2)), so your final answer should be y=(x+5)(x+2).
