Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
6305
StepStep-by-stepStepStep-by-step-by-step-by-step explanation:
multply
Answer:
$54.26
Step-by-step explanation:
Convert the percentage into a decimal by moving the decimal point 2 places to the left or divide by 100.
This will give you .0825.
Multiply this number by $50 and add it to it
The correct answer maybe
Actually I don't understand ur question
Rupees 937.36
think it's right
