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3 years ago

Solve Algebraically by Factoring. Solve for x. (x – 3)(x – 2) = 0

Mathematics

2 answers:

asambeis [7]3 years ago

6 0

X1=2 x2=3 hope this helps

wel3 years ago

6 0

Answer:

3,2

Step-by-step explanation:

(x - 3)(x - 2) = 0

x - 3 = 0 or x - 2 = 0

x = 3 or x = 2

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Which of the following expressions are equivalent to

Leokris [45]

your question: 

Which of the following expressions are equivalent to - -8/-4

Choose all answers that apply:

- -8/4

None of the above

answer: 

C. None of the Above ~ the answer is -2

7 0

3 years ago

How to turn 40/3 into mixed fraction please give correct abs for brainliest..

12345 [234]

13 1/3 because 40 divided 3 is 13 ….

7 0

3 years ago

P URGENT I've got a timer going on but really need your help to answer this thank you!!

astraxan [27]

Given:

The radius of inner circle = 13 yd.

The width of the shaded region = 8 yd

To find the area of the shaded region.

Now,

The radius of the outer circle = 13+8 yd = 21 yd

Formula

The area of a circle of radius r unit is $\pi r^{2}$ sq unit.

$A = A_{1}-A_{2}$

where, $A$ = The area of the shaded region

$A_{1}$ = Area of the outer region

$A_{2}$ = Area of the inner region

Now,

$A_{1}$ $=$ $\pi (21^{2})$

$A_{1} = (3.14)(21)(21)$

$A_{1}$ $= 1384.74$ sq yd

And,

$A_{2}$ $=$ $\pi (13^{2})$

$A_{2} = (3.14)(13)(13)$

$A_{2}$ $= 530.66$ sq yd

Therefore,

$A = 1384.74-530.66$ sq yd

$A = 854.08$ sq yd

Hence,

The area of the shaded region 854.08 sq yd.

7 0

3 years ago

. Five plus a number divided by 2 is 9.

Tresset [83]

Answer:

Using a calculator, if you typed in 9 divided by 2, you'd get 4.5. You could also express 9/2 as a mixed fraction: 4 1/2.

4 0

3 years ago

Read 2 more answers

C and D are mutually exclusive events. Find P(C or D). P(C)= 3/7= P(D)= 4/7 P(C or D)

IgorLugansk [536]

Answer:

$P(C\ or\ D) = 1$

Step-by-step explanation:

Given

$P(C) = \frac{3}{7}$

$P(D) = \frac{4}{7}$

Required

$P(C\ or\ D)$

Since the events are mutually exclusive, then:

$P(C\ or\ D) = P(C) + P(D)$

So, we have:

$P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}$

Take LCM

$P(C\ or\ D) = \frac{3+4}{7}$

$P(C\ or\ D) = \frac{7}{7}$

$P(C\ or\ D) = 1$

3 0

3 years ago