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Dovator [93]
3 years ago
11

Scott sets up a volleyball net in his backyard. One of the poles, which forms a right angle with the ground, is 12 feet high. To

secure the pole, he attached a rope from the top of the pole to a stake 10 feet from the bottom of the pole. Find the length of the rope, rounded to the nearest tenth.

Mathematics
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

Length of the rope = 15.6 ft.

Step-by-step explanation:

Given:

Height of the pole from the ground = 12 ft

Adjacent distance from the pole = 10 ft

We have to find the length of the rope attached by Scott to secure the pole.

According to the question :

In forma  right angled triangle as shown in the figure.

We have to find the measure of the hypotenuse.

Length of rope = Hypotenuse measure

Let the length of the rope = "h" ft

Using Pythagoras formula.

⇒ (hypotenuse)=\sqrt{opposite^2+ adjacent^2}

⇒ Plugging the values.

⇒ h=\sqrt{12^2 + 10^2}

⇒ h=\sqrt{144 + 100}

⇒ h=\sqrt{244}

⇒ h=15.62 ft

The length of the rope, rounded to the nearest tenth is 15.6 ft.

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melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
3 years ago
In a garden club, 90% i ladie. The number of ladie i 12 more than 3 time the number of gentlemen. How many ladie and how many ge
wariber [46]

In the garden club there are 18 ladies and 2 gentlemen.

Given, In a garden club, 90% is ladies.

The number of ladies is 12 more than 3 times the number of gentlemen.

Let the total members be, x

the number of ladies be, l and the number of gentlemen be, g

according to the question,

l = 90x/100

l = 9x/10

also, l = 12 + 3g

g = (l - 12)/3

as, l + g = x

9x/10 + (9x/10 - 12)/3 = x

9x/10 + 9x/30 - 4 = x

36x/30 - 4 = x

6x/30 = 4

x = 20

so, ladies be, l = 9x/10 = 18

and gentlemen be, g = 20 - 18 = 2

Hence, in the garden club there are 18 ladies and 2 gentlemen.

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1 year ago
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3 years ago
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A fruit vendor sells 60 pieces of fruit that are either apples or oranges. There are 12 more apples than oranges.
Hunter-Best [27]

Answer:

a. let x be the number of apples and let y be the number of oranges

x + y = 60

x = y + 12

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Step-by-step explanation:

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3 years ago
Your neighbor needs to put a fence around her front yard and a seperate fence around her backyard. Her front yard is 65 feet lon
elena-14-01-66 [18.8K]
Front yard
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Back yard
45+45+35+35=160
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380 feet
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3 years ago
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