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Anna007 [38]
3 years ago
7

Kamil and Sean share some money in the ratio 3:5. Sean gets $56 more than Kamil. How much do they get each?

Mathematics
1 answer:
liq [111]3 years ago
3 0
Let Kamil get x. Therefore Sean would get (x + 56).

Kamil and Sean are in the ratio:        3:5

That means:    x : (x + 56) = 3 : 5

x / (x + 56) = 3/5

5*x = 3*(x + 56)

5x = 3*x + 3*56

5x = 3x + 168

5x - 3x = 168

2x = 168

x = 168 / 2

x = 84

Therefore Kamil had, x = 84,  and Sean had (x + 56) = 84 + 56 =  140

Kamil had $84 and Sean had $140
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Answer:

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Step-by-step explanation:

The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.

For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773

To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649

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