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4 years ago

How to make a table for y=4

2 answers:

6 0

4 is the rate, so in the first row on the x-axis column add 1 and in the y-axis column add 4. The next row would be x(2) y(8) ect...

Simora [160]4 years ago

4 0

Puh 4 and each rows and it gonna make 4

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Cylinder A is mathematically similar to cylinder B. The height of cylinder A is 10cm and its surface area is 440cm2 . The surf

Pie

Answer:

$440 = 2\pi {r}^{2} + 2\pi(r)10 \\$

$3960 = 2\pi {r}^{2} + 2\pi(r)h$

$\frac{3960 = 2\pi {r}^{2} + 2\pi(r)h}{440 = 2\pi {r }^{2} + 2\pi(r)10 }$

$9 = \frac{h}{10}$

h=90

5 0

3 years ago

A credit card company charges 18.6% percent per year interest. Compute the effective annual rate if they compound, (a) annualy,

Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

$I=C(1+\frac{r}{n})^{nt}-C$

where

C = Amount of the credit granted

r = nominal interest per year

n = compounding frequency

t = the length of time the interest is applied. In this case, 1 year.

In the special case the interest rate is compounded continuously, the interest is given by

$I=Ce^{rt}-C$

(a) Annually

$I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)$

The effective annual rate is 18.6%

(b) Monthly

There are 12 months in a year

$I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)$

The effective annual rate is 20.27%

(c) Daily

There are 365 days in a year

$I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)$

The effective annual rate is 20.43%

(d) Continuously

$I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)$

The effective annual rate is 20.44%

3 0

3 years ago

Determine how many solutions each equation has and solve each equation using the quadratic formula.

Vikki [24]

Answer:

9 ± 3 i √ 7 / 2

Step-by-step explanation:

hope this helps

7 0

4 years ago

A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

4 years ago

Iron Man Training While training for an iron man competition, Tony bikes for 60 miles and runs for 15 miles. If his bikes speed

ivolga24 [154]

Answer:

Tony biked 1 hour 40 minutes and run 3 hours 20 minutes.

Step-by-step explanation:

How long did Tony speed on his bike?

Let s to be Tony's running speed, then 8s is Tony's biking speed

Let's recall that Time = Distance/Speed

Bike time + Running time = 5 hrs

Replacing with the real values, we have:

60/8s + 15/s = 5

8s as Lowest Common Denominator

60 + 8 * 15 = 5 * 8s

60 + 120 = 40s

-40s = -180

s = -180-40

s = 4.5 ⇒ 8s = 36

Tony run at 4.5 mph and biked at 36 mph

Now, we can calculate the time, this way:

Bike time = Bike distance/Bike speed

Replacing with the real values, we have:

Bike time = 60/36

Bike time = 5/3 (Dividing by 12)

5/3 hours * 60 = 100 minutes or 1 hour 40 minutes

Running time = 5 hours - 1 hour 40 minutes = 3 hours 20 minutes

Tony biked 1 hour 40 minutes and run 3 hours 20 minutes.

4 0

3 years ago