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DiKsa [7]
3 years ago
10

Solve each equation by finding all roots x^4-16=0

Mathematics
2 answers:
Alexandra [31]3 years ago
4 0
Add both sides by 16
so you'll have x^4 =16
take the 4th root of both sides and you'll get x=  2
SashulF [63]3 years ago
3 0
{ x }^{ 4 }-16=0\\ \\ { x }^{ 4 }=16\\ \\ x=\pm \sqrt [ 4 ]{ 16 } \\ \\ \therefore \quad x=\pm 2
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Write the equation of the line in slope-intercept form.
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2 years ago
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pantera1 [17]

Answer:

89

Step-by-step explanation:

To find the value of the

<h3>Quadratic expression</h3>

when x = 5 we substitute x = 5 into the expression.

4x^2 - 3x + 4

putting x = 5

4(5)^2 - 3(5) + 4

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8 0
2 years ago
What is the derivative of this function: F(x)=(5e^4x)+(e^-x^6)
Fed [463]

Answer:

\dfrac{dF(x)}{dx} =20e^{4x}-6x^5e^{x^{-6}}

Step-by-step explanation:

The derivative of F(x) is calculated as follows:

\dfrac{dF(x)}{dx}=\dfrac{d}{dx} [(5e^{4x})+(e^{-x^6})]

\dfrac{dF(x)}{dx}=\dfrac{d}{dx} [(5e^{4x})]+\dfrac{d}{dx} [(e^{-x^6})]

\dfrac{dF(x)}{dx}=5\dfrac{d}{dx} [(e^{4x})]+\dfrac{d}{dx} [(e^{-x^6})]

using the chain rule we find that

\dfrac{d}{dx} [(e^{4x})]= \dfrac{d}{d(4x)} [(e^{4x})]+ \dfrac{d}{dx} [4x] = 4e^{4x},

\dfrac{d}{dx} [(e^{-x^6})] = \dfrac{d}{d(-x^6)} [(e^{-x^6})]+\dfrac{d}{dx} [(-x^6})]= -6x^5e^{-x^6};

therefore,

\dfrac{dF(x)}{dx}=5\dfrac{d}{dx} [(e^{4x})]+\dfrac{d}{dx} [(e^{-x^6})] =5(4e^{4x})-6x^5e^{x^{-6}}

\boxed{\dfrac{dF(x)}{dx} =20e^{4x}-6x^5e^{x^{-6}}}

8 0
3 years ago
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