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4 years ago

Use make a 10 to add

Mathematics

2 answers:

lions [1.4K]4 years ago

6 0

Do you want me to add something by 10? Well 10+5

Kruka [31]4 years ago

3 0

5+5 that one of the answers

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Please thanks please please thanks

monitta

Answer:

72 hope this helps you!?!?!!?

7 0

3 years ago

Solve for n: 3(n+6)≥3n+8

hodyreva [135]

Answer:

infinite solutions

Step-by-step explanation:

3(n+6)≥3n+8

3n+18≥3n+8 (distributive property)

18≥8 (subtracted 3n from both sides)

this will always be true so there are infinite solutions

7 0

3 years ago

Read 2 more answers

Find the area please

tatuchka [14]

Answer:

Step-by-step explanation:

Recall that the area of a triangle is given by:

$\displaystyle A = \frac{1}{2} bh$

In this case, the base is x and the height is y. Hence:

$\displaystyle A = \frac{1}{2} xy$

We can write the following ratios:

$\displaystyle \sin \alpha = \frac{x}{12} \text{ and } \cos \alpha = \frac{y}{12}$

Solve for x and y:

$\displaystyle x = 12\sin \alpha \text{ and } y = 12\cos \alpha$

Substitute:

$\displaystyle A = \frac{1}{2}\left(12\sin \alpha\right)\left(12\cos \alpha\right)$

And simplify. Hence:

$\displaystyle A = 72\sin \alpha \cos\alpha$

In conclusion, our answer is D.

6 0

3 years ago

Robert wants to build a square sandbox that has an area of 25 feet. How long will each side be?

vova2212 [387]

Area = SxS
So sqaure root 25 = 5ft.

8 0

3 years ago

Read 2 more answers

Ursula and Velda live 4 km apart. They leave their homes at the same time, walking towards each other. If Ursula walks at a rate

vladimir2022 [97]

Answer: 250 m

Step-by-step explanation:

Given

Distance between Ursula and Velda house is 4 km or 4000 m

Ursula walks at the rate of $400\ m/h\ or\ \frac{20}{3}\ m/min$

Velda walks at the rate of $600\ m/h\ or\ 10\ m/min$

Time taken by them to cover 4000 m is

$\Rightarrow \dfrac{4000}{400+600}=4\ h\ or\ 240\ min$

Distance covered by them 15 min before they meet

Ursula $=\frac{20}{3}\times 225=1500\ m$

Velda $=10\times 225=2250\ m$

The total length covered by them is $=1500+2250=3750\ m$

They are $4000-3750=250\ m$ apart before they meet

6 0

3 years ago