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3 years ago

PLEASEEE HELPPPPP 88 points!!

Mathematics

2 answers:

Artemon [7]3 years ago

5 0

Answer:

3pi/4 =x and 5pi/4 =x

Step-by-step explanation:

cos x + sqrt(2) = - cos x

subtract cos x from each side

cos x - cosx + sqrt(2) = - cos x - cos x

sqrt(2) = -2 cos x

Divide each side by -2

-sqrt(2) / 2 =-2 cos (x) /-2

-sqrt(2) /2 =cos (x)

Take the inverse cos of each side

cos(-1)(-sqrt(2) /2) =cos^-1(cos (x))

3pi/4 =x and 5pi/4 =x

pantera1 [17]3 years ago

5 0

Answer:

Here's your answer:

3pi/4 =x and 5pi/4 =x

cos x + sqrt(2) = - cos x

subtract cos x from each side

cos x - cosx + sqrt(2) = - cos x - cos x

sqrt(2) = -2 cos x

Divide each side by -2

-sqrt(2) / 2 =-2 cos (x) /-2

-sqrt(2) /2 =cos (x)

Take the inverse cos of each side

cos(-1)(-sqrt(2) /2) =cos^-1(cos (x))

3pi/4 =x and 5pi/4 =x

Step-by-step explanation:

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triangles abc and def are similar. the lengths of the sides of abc are 56, 64, and 72. the length of the largest side of def is

Yuki888 [10]

Answer:

196

Step-by-step explanation:

70/252= 3.5

56x3.5=196

4 0

3 years ago

Which street is parallel to 1st Ave?

mestny [16]

Answer:

i believe its the second ave

6 0

3 years ago

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0

1 year ago

Jared made 12 3/4 cups of snack mix for a party.His guests eat 2/3 of the mix.How manysnack mix did his guest eat?

Fantom [35]

Answer:

<h3>The number of snacks did Jared's guest eat is $12\frac{1}{12}$ </h3>

Step-by-step explanation:

Given that Jared made $12\frac{3}{4}$ cups of snack mix for a party.

Let x be the cups of snacks mix made by Jared.

Therefore $x=12\frac{3}{4}$

His guests eat $\frac{2}{3}$ of the mix.

Let y be the guest eated snacks mix

Therefore $y=\frac{2}{3}$

<h3>To find how many snack mix did his guest eat :</h3>

Let z be the number of snacks did Jared's guest eat

Therefore z=x-y

$z=12\frac{3}{4}-\frac{2}{3}$

$=\frac{51}{4}-\frac{2}{3}$

$=\frac{51(3)-2(4)}{4\times 3}$

$=\frac{153-8}{12}$

$=\frac{145}{12}$

$=12\frac{1}{12}$

Therefore $z=12\frac{1}{12}$

<h3>Therefore the number of snacks did Jared's guest eat is $12\frac{1}{12}$ </h3>

5 0

4 years ago

In a population of 400,000 people, 160,000 are infected with a virus. After a person becomes infected and then recovers, the per

Margarita [4]

Answer:

Number of people that will be infected in 4 years is 252,610.

Step-by-step explanation:

The number of people that will be infected in 4 years can be calculated as follows:

Number of people that will be infected in year 1 = 160,000

Number of people that will not be infected in year 1 = 400,000 - 160,000 = 240,000

Number of people that will be infected in year 2 = Number of people that will not be infected in year 1 * 15% = 240,000 * 15% = 36,000

Number of people that will not be infected in year 2 = Number of people that will not be infected in year 1 - Number of people that will be infected in year 2 = 240,000 - 36,000 = 204,000

Number of people that will be infected in year 3 = Number of people that will not be infected in year 2 * 15% = 204,000 * 15% = 30,600

Number of people that will not be infected in year 3 = Number of people that will not be infected in year 2 - Number of people that will be infected in year 3 = 204,000 - 30,600 = 173,400

Number of people that will be infected in year 4 = Number of people that will not be infected in year 3 * 15% = 173,400 * 15% = 26,010

Therefore, we have:

Number of people that will be infected in 4 years = Number of people that will be infected in year 1 + Number of people that will be infected in year 2 + Number of people that will be infected in year 3 + Number of people that will be infected in year 4 = 160,000 + 36,000 + 30,600 + 26,010 = 252,610

6 0

3 years ago