Ask question

Ask question

All categories

4 years ago

8

At 8 A.M., the temp was 13'F below zero. By 1 P.M., the temp rose 22'F and by 6 P.m. dropped 14'F. What was the temperature at 6

P.M.? .

1 answer:

san4es73 [151]4 years ago

7 0

-13 + 22 = 9
9 - 14 = -5
At 6 P.M. the temperature was -5 Fahrenheit.

You might be interested in

Which expression is equivalent to 10x - (8x +3)

Verdich [7]

Answer:

you forgot to add the options of the answer

5 0

3 years ago

PLEASE HELP ILL GIVE BRAINLIEST!!

leonid [27]

Answer:

g(5) = 5

Step-by-step explanation:

g(5) is really g when x=5 so we have to use the function g(x) when x≥2

g(5) = 2x-5 when x=5

g(5) = 2*5 -5 = 10-5 = 5

6 0

3 years ago

Solve for y. 2/3 + y - 4/5 = 1/3 Enter your answer in the box. y =

erica [24]

<span>2/3 + y - 4/5 = 1/3
y = 1/3 - 2/3 + 4/5
y = -1/3 + 4/5
y =-5/15 + 12/15
y = 7/15</span>

3 0

3 years ago

Read 2 more answers

I have a genuine question. Please Read :D

nikitadnepr [17]

Answer:

I have this deck that works pretty well!!!

Ice wizard, wizard, electro wizard, princess, firecracker, baby dragon and skeletons.

It wins like almost every match and my friends are using this deck too!!

TRY IT OUT YEA!!

4 0

3 years ago

Simplifly the expression 64^7/12

Evgesh-ka [11]

Answer:

$8\sqrt{2}$

Step-by-step explanation:

we have

$64^{\frac{7}{12}}$

we know that

$64=2^{6}$

substitute

$64^{\frac{7}{12}}=(2^{6})^{\frac{7}{12}}\\ \\=(2)^{\frac{6*7}{12}} \\ \\=(2)^{\frac{7}{2}} \\ \\=\sqrt{2^{7}}\\ \\=2^{3}\sqrt{2} \\ \\=8\sqrt{2}$

7 0

3 years ago