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Zepler [3.9K]
3 years ago
8

You purchased a boat for $19,000 and can expect the boat to depreciate at an annual rate of 7.3%. What will the value of your ca

r be 4 years after purchasing it
Mathematics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

$14,030.48

Step-by-step explanation:

We can use the following formula to solve:

A=P(1-r)^t

<em>P = principal value </em>

<em>r = rate (decimal) </em>

<em>t = time (years)</em>

<em />

First, lets change 7.3% into a decimal:

7.3% -> \frac{7.3}{100} -> 0.073

Next, plug in the values:

A=19,000(1-0.073)^4

A=14,030.48

The value will be $14,030.48

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A unit rate means for one, so in this case they mean for one pound of the horse feed which brand sells the highest. You would divide the cost into the number of pounds for each brand. Now, compare all the brands and see which one is highest.
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3 years ago
Read 2 more answers
Omar drew a number line that went from -10 to 10 and used it to compare integers. Which statement is true?
Evgen [1.6K]

Answer:

-7 < -3 because -7 is located to the left of -3 on a number line.

Step-by-step explanation:

This is because -7 is on the left of the -3. In negatives -3 is greater than -7. If it was positive then 7 would be greater than 3. So the answer is A. -7 < -3 because -7 is located to the left of -3 on a number line

4 0
3 years ago
Find the value of 5y-11 given that -5y=-45
Vlada [557]

Answer:

34

Step-by-step explanation:

-5y=-45

y=-45/-5

=9

y=9

then

5y-11=5×9-11

=45-11

=34

6 0
3 years ago
Read 2 more answers
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
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