Question

For z = 2cis 60°, find z4 in rectangular form.

Answer 1

By DeMoivre's theorem,

$z=2\mathrm{cis}60^\circ\implies z^4=2^4\mathrm{cis}(4\times60)^\circ=16\mathrm{cis}\,240^\circ$
$z^4=16(\cos240^\circ+i\sin240^\circ)$
$z^4=16\left(-\dfrac12-i\dfrac{\sqrt3}2\right)$
$z^4=-8-i8\sqrt3$

Answer 2

Answer:

For plato users the answeris -8-8$\sqrt{3i}$

Step-by-step explanation: