It is defined as the common number of two integers, which is the lowest number that is a multiple of two or more numbers. The full name of LCM is the least common multiple.

It is given that:

The number nearest to 10000 is exactly divisible by 3, 4, 5, 6, 7, and 8.

TO find the number:

Find the LCM of 3, 4, 5, 6, 7, and 8:

LCM = 760

= 10000/760

There are two possibilities:

= 10000 - 760 = 9240

or 10000 + (840 - 760) = 10080

The nearest number = 10080

Thus, the nearest number is 10080 if the number is nearest to 10000 which is exactly divisible by 3, 4, 5, 6, 7, and 8.

Learn more about the LCM here:

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3 0

2 years ago

Complete the equation of the line through (-9,-7) and (-6,-3)

Annette [7]

The equation of the line through (-9, -7) and (-6, -3) is $y+3=\frac{4}{3}(x+6)$

<u>Solution:</u>

Given, two points are (-9, -7) and (-6, -3)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

The slope of the line "m" is given as:

$\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

So slope of our line $=\frac{-3-(-7)}{-6-(-9)}=\frac{-3+7}{-6+9}=\frac{4}{3}$

Now, let us find the line equation using point slope form:

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) \text { where } \mathrm{m} \text { is slope and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { is point on the line. }$

By substituting the values we get,

$\text { Then, line equation } \rightarrow y-(-3)=\frac{4}{3}(x-(-6))$

$y+3=\frac{4}{3}(x+6)$

Hence, the line equation is $y+3=\frac{4}{3}(x+6)$

8 0

3 years ago