Y = - 4x^2 - 3x + 3 This thing is complex with fractions. I have to work it out.
y = -4(x^2 + 3/4 x) + 3
y = -4(x^2 + 3/4 x + (3/8)^2 ) + 3
y = -4(x + 3/8)^2 +3 + 4*(9/64)
y = -4(x + 3/8)^2 + 3 + 9/16
y = -4(x + 3/8)^2 + 3 9/16 Equation in Vertex form. <<<<< answer
y = -4(x + 0.385) + 3.5625 Equation in Vertex form. <<<< answer
One is in decimal form. One in fraction form.
the vertex (-3/8, 3 9/16) or alternately
the vertex (-0.375,3.5625)
You might want the graph to confirm my answer.
Answer:
21
Step-by-step explanation:
Since this is an equilateral triangle, all sides are equal.
3x-6 = 2x+3
Move like terms to one side
x = 9
Now we plug 9 back in for x
2(9) + 3
=18 + 3
=21
Answer:
Step-by-step explanation:
me
Answer:
d=rt In this problem we are looking for the distance, but we will have to go about it indirectly. If she's traveling the same exact road going and returning, then the distance traveled both ways is exactly the same. Since d = rt, and d is the same, by the substitution property, if and , then , and . So we need to rt for the trip going, rt for the trip returning and set them equal to each other and solve for t. Going is a rate of 24, and the time is t (since we don't know t), and returning is a rate of 30, and the time is 13 1/3-t. (If the whole trip takes 13 1/3 hours, and t is the time going, then the time returning is the difference between the total time and the going time. That concept is one that baffles most algebra students!). So our r1t1 is 24t, and our r2t2 is 30(13 1/3 - t). Set them equal to each other and that will look like this: That fraction of 40/3 is 13 1/3 made into an improper fraction. Distributing that we will have and 54t = 400. That means that t = 7.407. We have time, and that's great, but we need distance! Go back to one of your equations for distance and sub in t and solve for d. d = 24t, and d = 24(7.407), so d = 177.768 miles.
Answer:
y - 2 = - 4(x + 2)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - 4 and (a, b) = (- 2, 2 ) , then
y - 2 = - 4(x - (- 2) ) , that is
y - 2 = - 4(x + 2)
