Step-by-step explanation:
the price charged for 100 students reflects the cost per student that applies to the order as a whole.
100 * 6 = $600, so the fixed cost is 750-600 = 150.
...
We can check this by substituting in the other equation.
Does 150*6 + 150 = 1050?
150*6=900
900+150 = 1050.
Yes, it does
...
We can express this relationship by the equation:
y = mx + b
where
y = total cost
m = $6 per student
x = number of students
b = fixed costs = 150
y = 6x + 150
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
area of each triangular base = 24
area of bottom rectangular face = 160
area of back rectangular face = 120
area of sloped rectangular face = 200
Total = 504
Step-by-step explanation:
Answer:
Plain is $7 and Holiday is $15
Step-by-step explanation:
Castel: 2p + 5h = 89
Kali: 9p + 10h = 213
Double Castel's: 4p + 10h = 178
Subtract fro Kali's 9p + 10h = 213
- 4p + 10h = 178
5p = 35
p = 7 Plain is $7
Substitute 7 into one of the equations and solve for h:
2(7) + 5h = 89
14 + 5h = 89
5h = 75
h = 15 Holiday is $15
Answer:
e=1
Step-by-step explanation:
