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harkovskaia [24]
3 years ago
11

Ginger has 12 plastic bead containers. The containers measure 1 inch on each side. How many rectangular prisms, each with a diff

erent-size base, could Ginger make by stacking all the bead containers
Mathematics
1 answer:
nignag [31]3 years ago
4 0
12 shjakakchvwbsmaouf didn’t be. Yeh s Wuxi m you don’t know what you mean
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I need help asap )/)/)/)
Andrej [43]

Answer:

$49.20

Step-by-step explanation:

6 0
3 years ago
Given ​ f(x)=x2+14x+40 ​.<br><br><br> Enter the quadratic function in vertex form in the box.
sammy [17]
Please indicate exponentiation using " ^ "   Thanks.

f(x)=x2+14x+40 => <span>f(x)=x^2+14x+40

Next, complete the square:

</span>f(x)=x^2+14x+ 49 - 49 +40 = (x+7)^2 - 9 

Write this in the form y = (x+7)^2 - 9  or y + 9 = (x+7)^2
Comparing this result to y = a(x-h)^2 + k, we see that h = -7 and k=-9

In vertex form, the equation is y + 9 = (x+7)^2 and the vertex is at (-7, -9).
8 0
3 years ago
= 9x2 +9x -18,/<br> 3x +6
Ede4ka [16]

Answer:24+3x

Step-by-step explanation:

maybee i just used photomath

3 0
2 years ago
Express the given quantity as a single logarithm and simplify: 3logx+2log(y-2)-5logx
storchak [24]
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+2log(y−1)−5log(x)</span><span> 
</span>
Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span> 
</span>
Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span> 
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span> 
</span>
Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method. 
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span> 
</span>
Simplify each term<span>. 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span> 

</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span> 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span> 
</span>
Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)

</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span> 
</span>log(x^3(y^2−2y+1)/x^5)

Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>. 
</span><span>log(<span><span><span>y^2</span>−2y+1/</span><span>x^2</span></span>)</span><span> 

</span>Rewrite 1<span> as </span><span><span>1^2</span>.</span> 
<span><span>y^2</span>−2y+<span>1^2/</span></span><span>x^2</span>

Factor<span> by </span>perfect square<span> rule. 
</span><span>(y−1<span>)^2/</span></span><span>x^2</span>

Replace into larger expression<span>. 
</span>
<span>log(<span><span>(y−1<span>)^2/</span></span><span>x^2</span></span>)</span> 
3 0
3 years ago
If the map ratio of a map is 1:100000 and the distance between two
dsp73

Answer:

Given that,

Map scale = 1:100000

Map distance = 8cm

Therefore,

MD ÷ AD = 1 ÷ 100000

8 ÷ AD = 1 ÷ 100000

AD = 8 × 100000

AD = 800000

8 0
2 years ago
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