Answer:
The distribution is approximately normal with mean = 2.8 and standard error = 0.4
Step-by-step explanation:
We are given;
Mean; μ = 2.8
Standard deviation; σ = 4
Sample size; n = 100
Now, the central limit theorem states that the sample mean with a sample size(n) from a population mean (μ) and population standard deviation(σ) will, for large value of n, have an approximately normal distribution with mean μ and standard error as (σ/√n)
The sample size is 100 and thus it's very large because it's bigger than minimum of 30 for approximate distribution.
Thus, SE = (σ/√n) = 4/√100 = 4/10 = 0.4
Thus,from the central limit theorem I described, we can say that the distribution is approximately normal with mean = 2.8 and standard error = 0.4
