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Aloiza [94]
2 years ago
15

PLEASE HELP!! URGENT!!!

Mathematics
1 answer:
Tanya [424]2 years ago
4 0

Answer:

<h2>NS = 24</h2>

Step-by-step explanation:

The medians of the triangle are divided in a ratio of 1:2. Therefore:

\dfrac{PS}{NP}=\dfrac{1}{2}

We have NP = 16. Substitute:

\dfrac{PS}{16}=\dfrac{1}{2}             <em>multiply both sides by 16</em>

PS=8

NS = NP + PS

Therefore

NS = 16 + 8 = 24

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Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

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2 years ago
Lloyd has a fish tank that is 8 inches high, 14 inches long, and 6 inches wide. A fish tank has a length of 14 inches, height of
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Step-by-step explanation:

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The answer is c!!!! hope this helps
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