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Papessa [141]
3 years ago
15

Solve −8x ≤ 2.

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0
-8x ≤ 2         
Divide both sides by negative 8. Remember that dividing both sides by a negative number flips the direction of the inequality.
x ≥ -(1/4)
-(1/4) can also be written as -0.25
Answer is C) x ≥ -0.25
zavuch27 [327]3 years ago
4 0
Hello Neisha

-8x ≤ 2

Divide both sides by -8

-8x≤ 2/-8

x ≥ -0.25

The correct answer is option C
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\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

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