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Sonbull [250]
3 years ago
8

What is the solution of log(2t+4) = log(14-3t)?

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

log(2t+4)=log(14-3t)

[Divide both sides with log, since both sides have log, division removes the log]

2t+4=14-3t

2t+3t=14-4

5t=10

t=2

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Please help me and answer with work! Due tomorrow!​
ELEN [110]

Answer:

Step-by-step explanation:

a.

The angles given are 62° and 90°.

We know sum of angles in any triangle is 180° so the third angle must be 180-90-62 = 28°

We can find the sides if we know trigonometric functions

sin28° = opp. side/ hypothenuse = CA/BA = 8/BA

BA = 8/sin 28° ≈ 17

tan62°= opp.side/adj.side= BC/AC = BC/8

BC = 8 · tan62° ≈ 15

b.

We are given 2 sides 8.5 and 6.5 and that one angle is right, so the triangle is a right triangle, therefore we can apply Pythagorean Theorem to find the third side.

6.5² +FD² = 8.5², subtract 6.5² from both sides

         FD² = 8.5²- 6.5², square and combine like terms

         FD² = 30, square-root both sides

          FD = √30

          FD ≈ 5.47722, round to the nearest tenth

          FD ≈ 5.5

We can find the angles if we know trigonometric functions.

sin ∡D = FE/DE = 6.5/8.5

     ∡D = sin^-1 (6.5/8.5)

    ∡D ≈ 49.9°

cos ∡E = FE/DE = 6.5/8.5

      ∡E = cos^-1 (6.5/8.5)

      ∡E ≈ 40.1°

6 0
2 years ago
I don’t get the second question.
Bess [88]
<h2>Good morning,</h2>

<em><u>Answer</u></em>:

The quadratic equation is :  x²+x+1=0

<u><em>Step-by-step explanation:</em></u>

Generally:

let S be the sum of the roots z₁ and z₂

and P be the product of the roots z₁ and z₂

then z₁ and z₂ are the solutions for the equation:  x² − Sx + P = 0

Now,

S=-1 and P=1 then the equation is x²+x+1=0.

______

:)

8 0
3 years ago
9x−4=−1 how do i show my work for this?
AnnZ [28]

Answer:

x = 1/3

Step-by-step explanation:

9x - 4 = -1

9x = -1 + 4

9x = 3

8 0
3 years ago
Solve the radical equation x – 7 = square root of -4x+28. Which statement is true about the solutions to the radical equation? T
Julli [10]

Answer:

x = 3 and 7

There are two true solutions.

Step-by-step explanation:

To solve x-7 = \sqrt{-4x+28}, use inverse operations by squaring both sides of the equal sign.

(x-7)^2 = (\sqrt{-4x+28})^2\\x^2-14x+49 = -4x+28\\x^2-14x+4x+49-28 = 0\\x^2-10x+21=0

The quadratic expression can be factored into binomials and set equal to 0 by the zero product property to find x.

(x - 3) ( x - 7) = 0

x-3 = 0 so x=3

x-7 = 0 so x=7

Now check each solution into the original equation to be sure it solve the solution and is not extraneous.

7-7 = \sqrt{-4(7)+28}\\ 0=0

and

3-7 = \sqrt{-4(3)+28}\\[tex]-4 = \sqrt{16}\\-4 =-4[/tex]

3 0
3 years ago
What is the length of an arc with a measure of 45 in circle with a diameter of 4 miles?
Radda [10]
The length of the arc will be given by:
C=θ/360×π×d
thus plugging our values we get:
C =45/360×π×4
C=0.5π~1.5708 miles
6 0
3 years ago
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