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Tju [1.3M]
3 years ago
15

Solve the radical equation x – 7 = square root of -4x+28. Which statement is true about the solutions to the radical equation? T

here are no true solutions. There are two true solutions. There is one extraneous solution, with a value greater than 4. There is one true solution, with a value greater than 6.
Mathematics
1 answer:
Julli [10]3 years ago
3 0

Answer:

x = 3 and 7

There are two true solutions.

Step-by-step explanation:

To solve x-7 = \sqrt{-4x+28}, use inverse operations by squaring both sides of the equal sign.

(x-7)^2 = (\sqrt{-4x+28})^2\\x^2-14x+49 = -4x+28\\x^2-14x+4x+49-28 = 0\\x^2-10x+21=0

The quadratic expression can be factored into binomials and set equal to 0 by the zero product property to find x.

(x - 3) ( x - 7) = 0

x-3 = 0 so x=3

x-7 = 0 so x=7

Now check each solution into the original equation to be sure it solve the solution and is not extraneous.

7-7 = \sqrt{-4(7)+28}\\ 0=0

and

3-7 = \sqrt{-4(3)+28}\\[tex]-4 = \sqrt{16}\\-4 =-4[/tex]

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vladimir1956 [14]
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It is where cos(4x-π) = 0

cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2

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<h3>a.</h3>

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<h3>b.</h3>

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<h3>c.</h3>

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