Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±
* √[(^ρ(1-^ρ))/n]
=
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!
Answer:
132 is the answer
Step-by-step explanation:
Answer:
The Answer:
.
Step-by-step explanation:
x+2y=z
minus x both sides
2y=z-x
divide by 2 both sides
The Answer:

The amount that the credit union will finance is $24169.60
We have given that the cost of the car is $22,346. 16
and the credit union required 10% down payment
and sale tax=7.6%
The license and title charges are $125. 13.
We have to determine that the amount that the credit union will
finance Now we have sale tax 7.6% for $22,346. 16
Therefore, we get

<h3>What is the amount that the credit union finance ?</h3>
credit union finance=cost of car+sales tax+the license and title charges.

Therefore, the amount that the credit union will finance is $24169.60
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