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frozen [14]
3 years ago
11

Three years ago Tom was twice as old as Jean, and in two years the sum of their ages will be 28 years. Find their present ages.

Mathematics
2 answers:
natali 33 [55]3 years ago
4 0

Answer:

Tom is 15 years old and Jean is 9 years old

Step-by-step explanation:

Let call:

x: the age of Tom

y: the age of Jean

From the sentence: three years ago Tom was twice as old as Jean, we get the first equation:

(x-3)=2(y-3)

Solving for x:

x=2y-6+3

x=2y-3

From the sentence: in two years the sum of their ages will be 28 years, we get the second equation:

(x+2)+(y+2)=28

Solving:

x+y+4=28

x+y=28-4

x+y=24

Now, we have two equations with two incognites:

equation 1: x=2y-3

equation 2: x+y=24

For finding the values of x and y we need to replace the x = 2y-3 on the second equation and solve for y, as following:

(2y-3)+y=24

2y+y-3=24

3y=27

y=27/3

y=9

Then, we Replace y=9 on the first equation and get:

x=2(9)-3

x=18-3

x=15

Now, we have the values of x and y that satisfy the two formulate equation, so the answer is x equal to 15 and y equal to 9. So, Tom is 15 years old and Jean is 9 years old

lubasha [3.4K]3 years ago
3 0

Answer:

Jean is 9 and Tom is 15.

Step-by-step explanation:

3 years ago, Tom was 12 and Jean was 6, hence Tom was twice as old as Jean.  

Since that was their age 3 years ago, they are currently 15 (Tom) and 9 (Jean).  

Add 2 years to each of these ages, you get 17 and 11.

17 + 11 = 28

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Given

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