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4 years ago

A car dealership decreased the price of a certain car by 4%. The original price was

2 answers:

6 0

%change=100(final-initial)/initial,

%change=100(New price-Original price)/Original price

(Original price*%change)/100=New price-Original price

New Price=(Original price*%change+100*Original price)/100

New Price=Original price(100+%change)/100

Since %change is -4%...

New Price=0.96(Original price)

...

Since original price is $45400

New Price=0.96(45400)

New Price=$43584

Naya [18.7K]4 years ago

3 0

Answer:

(a) $\text{New Price}=0.96\times \text{Original Price}$

(b) The new price of car is $43584.

Step-by-step explanation:'

(a)

The original price of car is $45400.

It is given that the car dealership decreased the price of a certain car by 4%.

$\text{New Price}=\text{Original Price}-\frac{4}{100}\times \text{Original Price}$

$\text{New Price}=(1-\frac{4}{100})\times \text{Original Price}$

$\text{New Price}=\frac{96}{100}\times \text{Original Price}$ \

$\text{New Price}=0.96\times \text{Original Price}$

(b)

Using part (a), we get

$\text{New Price}=0.96\times \text{45400}$

$\text{New Price}=43584$

Therefore the new price of car is $43584.

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A store has a sale on paper cups, 200 cups for $15.00. During the sale, what is the unit price per cup?

Anna35 [415]

Answer:

it's either 200:15 or 20:15 or 15:20

Step-by-step explanation:

6 0

4 years ago

Suppose that f(x) is the (continuous) probability density function for heights of American men, in inches, and suppose that f(69

anastassius [24]

Answer:

(a) 7.6%

(b) 46.2% 42.4%

Step-by-step explanation:

(a)According to the definition of Continuous probability distribution

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x + h) - F(x - h)}{(x + h) - (x - h)}$

$f(69) = \frac{F(69 + 0.2) - F(69 - 0.2)}{0.4}$

⇒ 0.19 × 0.4 = F(69.2) - F(68.8)

⇒ F(69.2) - F(68.8) = 0.076

⇒ 7.6%

(b) Given F(69) = 0.5

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x) - F(x - h)}{x - (x - h)}$

$f(69) = \frac{F(69) - F(69 - 0.2)}{0.2}$

⇒ 0.19 × 0.2 = F(69) - F(68.8)

⇒ F(68.8) = 0.5 - 0.038 = 0.462

⇒ 46.2%

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x) - F(x - h)}{x - (x - h)}$

$f(69) = \frac{F(69) - F(69 - 0.4)}{0.4}$

⇒ 0.19 × 0.4 = F(69) - F(68.8)

⇒ F(68.8) = 0.5 - 0.076 = 0.424

⇒ 42.4%

5 0

3 years ago

Whats 123456+65432134

Flauer [41]

Answer:65555590

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve the system. <br> y= -2x + 1<br><br> y= 2x - 3

Neporo4naja [7]

Equation 1: y = -2x + 1

Equation 2: y = 2x - 3

Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.

-2x + 1 = 2x - 3

1 = 4x - 3

4 = 4x

x = 1

Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.

y = 2x - 3

y = 2(1) - 3

y = 2 - 3

y = -1

Hope this helps!! :)

5 0

3 years ago

Read 2 more answers

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago