Answer:
The period of Y increases by a factor of
with respect to the period of X
Step-by-step explanation:
The equation
shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared
with
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of
with respect to the period of X
North divided by Total (Total of North, South, Central, East, and West)
North = 1
South = 4
Central = 2
East = 3
West = 2
North ÷ Total
1 ÷ (1 + 4 + 2 + 3 + 2 )
1 ÷ (12)
= 
Answer: B
She would need to put 1 3/4 more cups in.
A: 8*9= 72
B: euclidean theorem (35,63) (35,28) (7,28) (7,0) gcf= 7
C: 7(5+9)