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3 years ago

If John has 25 apples and adds 500 how much does he have?

Mathematics

2 answers:

Rom4ik [11]3 years ago

6 0

He would have 525 apples

OlgaM077 [116]3 years ago

4 0

Answer:

525 apples

Step-by-step explanation:

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Cmon fwm on dis one to

stich3 [128]

Answer:

x = 10.5

Step-by-step explanation:

we know that ZP = PX (its the midpoint of the rectangle)

11 = PX

ZP + PX = ZX

11+11 = ZX

22 = ZK

2x + 1 = 22

2x = 22 -1

2x = 21

x = 21/2

x = 10.5

3 0

2 years ago

Evaluate 3a2 + 4b2 for a = 2 and b = 3. O 168 48 O 36

Juliette [100K]

Answer:

Step-by-step explanation:

a=2

b=3

3a^2+4b^2

3(2)^2+4(3)^2

3(2)(2)+4(3)(3)

3(4)+4(9)

12+36

Hope this helps ;) ❤❤❤

8 0

2 years ago

Read 2 more answers

There are 17 kites in a kite-flying contest at the beach. There are 3 times as many box kites as butterfly kites. There are 2 mo

alina1380 [7]

C is your answer. 5x + 2 = 17

First let’s get them all in terms of x:
Box kites = 3x
Dragon kites = x + 2
Butterfly kites = x

Adding all those up:

x + 3x + x + 2 = 17
Combine like terms:
5x + 2 = 17

6 0

3 years ago

Read 2 more answers

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

3 0

2 years ago

A laboratory experiment requires 2400 milligrams of sugar. How many kilograms of sugar does the experiment require?

telo118 [61]

Answer:

0.0024

Step-by-step explanation:

1 killogram=1000000

5 0

3 years ago