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4 years ago

10

How do I draw a quadrilateral whose diagonals bisects each other at right angles with all sides equal in length and opposite sid

es are parellel?

1 answer:

KIM [24]4 years ago

4 0

The shape you described is a rhombus

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Answer:

$-2t^2+3t+4$ or $-2t^2+3t^1+4t^0$

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The equation is already written in standard form.

You write the largest exponents to the left and the smallest to the right.

<u>Your expression: </u> $-2t^2+3t+4$ <u> can also be expressed as this below:</u>

$-2t^2+3t^1+4t^0$

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If t was 2...

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Same result:

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4 years ago