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Romashka [77]
4 years ago
12

What is 575% written as a mixed number

Mathematics
2 answers:
wlad13 [49]4 years ago
5 0
575% as a mixed number would be 5 3/4
-BARSIC- [3]4 years ago
4 0
Hi there! 575% as a decimal is 5.75, 5.75=5 75/100. Now, we simplify 75/100. 75/25=3 and 100/25=4. In this case, we have a fraction of 3/4. Now, we have 5 3/4. Therefore, 575% written as a mixed number is 5 3/4.
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What is the final amount if 1634 is decreased by 3% followed by a 4% increase? Give your answer rounded to 2 DP.
Blizzard [7]

Answer:

1648.37

Step-by-step explanation:

1634*0.97*1.04

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Select the proper inverse operation to check the answer to 25 − 13 = 12.
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That would be A. Just work backwards starting with your answer.
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A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
nasty-shy [4]

Answer:

(9.6, 25.7) is a 80% confidence interval for the average net change in a student's score after completing the course.

Step-by-step explanation:

We have n = 6, \bar{x} =  17.6667 and s = 13.3367. The confidence interval is given by

\bar{x}\pm t_{\alpha/2}(\frac{s}{\sqrt{n}}) where t_{\alpha/2} is the \alpha/2th quantile of the t distribution with n-1=5 degrees of freedom. As we want the 80% confidence interval, we have that \alpha = 0.2 and the confidence interval is 17.6667\pm t_{0.1}(\frac{13.3367}{\sqrt{6}}) where t_{0.1} is the 10th quantile of the t distribution with 5 df, i.e., t_{0.1} = -1.4759. Then, we have 17.6667\pm (1.4759)(\frac{13.3367}{\sqrt{6}}) and the 80% confidence interval is given by (9.6, 25.7)

6 0
3 years ago
Kodi earns $33 for walking 4 dogs. at this rate, how much will she earn if she walks 7 dogs?
Allisa [31]

Answer:

57 Dollars, and 75 cents. (57.75

Step-by-step explanation:

Assuming she earns 8 dollars and 25 cents per dog,

8.25x7 = 57.75

<u>How I got 8.25:</u>

33/4 = 8.25

Hope this helped~!

4 0
4 years ago
A random sample of medical files is used to estimate the proportion p of all people who have blood type B. (a) If you have no pr
GaryK [48]

Answer:

a) 752 medical files should be included.

b) 372 medical files should be included.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Question a:

This is n for which M = 0.03. We have no estimate, so we use \pi = 0.5. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.645*0.5

\sqrt{n} = \frac{1.645*0.5}{0.03}

(\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2

n = 751.67

Rounding up:

752 medical files should be included.

Question b:

Now we have that:

\pi = \frac{13}{90} = 0.1444

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.1444*0.8556}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.1444*0.8556}

\sqrt{n} = \frac{1.645\sqrt{0.1444*0.8556}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.1444*0.8556}}{0.03})^2

n = 371.5

Rounding up:

372 medical files should be included.

8 0
3 years ago
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