Given:
Cards labelled 1, 3, 5, 6, 8 and 9.
A card is drawn and not replaced. Then a second card is drawn at random.
To find:
The probability of drawing 2 even numbers.
Solution:
We have,
Even number cards = 6, 8
Odd numbers cards = 1, 3, 5, 9
Total cards = 1, 3, 5, 6, 8 and 9
Number of even cards = 2
Number of total cards = 6
So, the probability of getting an even card in first draw is:



Now,
Number of remaining even cards = 1
Number of remaining cards = 5
So, the probability of getting an even card in second draw is:


The probability of drawing 2 even numbers is:



Therefore, the probability of drawing 2 even numbers is
. Hence, the correct option is (b).
Answer:
see the prime factors
Step-by-step explanation:
24= 6*4=3*2*2*2
=2*3*4
The middle one is the answer.
The -1 moves the graph down by one unit.
if it was |x-1| that would move it one unit right.
Answer:
108 student tickets, and 176 adult tickets were sold
Step-by-step explanation:
Adult ticket $8 Call the number of adult tickets sold "a"
Student ticket $5 Call the number of student tickets sold "s"
Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284
Then we create two different equations with the information given:
a + s = 284
8 * a + 5 * s = 1948
we can solve for s in the first equation as follows: s = 284 - a
and use it in the second equation
8 a + 5 (284 - a) = 1948
8 a + 1420 - 5 a = 1948
combining
3 a = 528
a = 528/3
a = 176
we find the number of student tickets using this answer in the substitution equation we used:
s - 284 - 176 = 108
Therefore 108 student tickets, and 176 adult tickets were sold.
Answer:
The distance is 8 cm
Step-by-step explanation:
The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...
BD² +AB² = AD²
BD² = AD² -AB² = 34² -30² = 256
BD = √256 = 16
The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.
distance from AB to the center = 16/2 = 8 . . . cm