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2 years ago

Q÷ 6 = 4 plzzzz helppp I need answerss ASAP

Mathematics

1 answer:

dalvyx [7]2 years ago

4 0

Answer:

q=24

Step-by-step explanation:

the opposite of division is multiplication so 4x6=24. then you check this by of course imputing your answer into the equation. 24 ÷ 6 =4

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66666666666666666666666666666666.00000008x47673655746

Furkat [3]

Answer:

3.1782437e+42

Step-by-step explanation:

8 0

3 years ago

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If Jane's shirt cost 20$, but she has a 15% off coupon, what is her cost before tax

alina1380 [7]

Answer:

Step-by-step explanation:

The discount on the shirt is 15%

Discount = price* discount rate

= 20 * 15%

= 20 * .15

The new price is the previous price minus the discount

new price = 20-3

new price = 17

8 0

2 years ago

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Please finish this equation and write the answer

olga55 [171]

Given:

The equation is:

$2540=\dfrac{22}{7}r^2(20)$

To find:

The solution for the given equation.

Solution:

We have,

$2540=\dfrac{22}{7}r^2(20)$

It can be written as:

$\dfrac{2540\times 7}{22\times 20}=r^2$

$\dfrac{17780}{440}=r^2$

$\dfrac{889}{22}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{889}{22}}=r$ [Radius cannot be negative]

$r=6.3568145$

$r\approx 6.36$

Therefore, the value of r is about 6.36 cm.

7 0

2 years ago

An equation is shown below: 8x + 2(x - 7) = 7x + 3x - 14 Part A: Solve the equation and write the number of solutions. Show all

Art [367]

$8x+2(x-7)=7x+3-14\\8x+2x-14=7x+3-14~~Distributive~property\\10x-14=7x-11~combine~like~terms\\
3x-14=-11~subtract~the~7x~from~both~sides\\
3x=3~add~14~to~both~sides\\x=1~divide~both~sides~by~3$

8 0

3 years ago

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18. In the figure, o is the center of the circle passing through P, Q, R and S. If angle SOQ = 150°, find the values of x and y.

AveGali [126]

Answer:

x = 75°

y = 105°

Step-by-step explanation:

Angle subtended on the circumference of the circle is half of the angle subtended on the center of the circle.

$\therefore m\angle SRQ = \frac{1}{2} \times m\angle SOQ\\\\\therefore x = \frac{1}{2} \times 150\degree \\\\\red{\bold{\therefore x =75\degree}} \\$

Quadrilateral PQRS is a cyclic quadrilateral.

$\therefore m\angle R + m\angle P= 180\degree \\\\\therefore x + y = 180\degree \\\\\therefore 75\degree + y = 180\degree \\\\\therefore y = 180\degree - 75\degree \\\\\purple {\bold {\therefore y = 105\degree}} \\$

3 0

3 years ago