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Yuliya22 [10]
3 years ago
14

find the total number of possible outcomes for four different cell phone models each of which has 3 different plans

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0
Hello!

I believe there are a total of 12 possible outcomes for this problem. Using simple math, you can just multiply 4 by 3 to get 12 possible outcomes but you can also get 12 outcomes by looking at the fact that since there are 3 plans in each of the 4 models, there are 12 ways that this could play out.

I hope this helps!
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Help 0.06 is 10 times as much as
Ipatiy [6.2K]

Answer:

0.06 is 10 times as much as 0.006

Step-by-step explanation:

let the number be x

as per the condition 0.06 is 10 times as much as x.

Solve for x:

10 times as much as x represents as 10 \times x

Then;

0.06 = 10 \times x                 ......[1]

Division property of equality states that you divide the same number to both sides of an equation.

divide by 10 to both sides in equation [1];

\frac{0.06}{10} = \frac{10x}{x}

Simplify:

x = 0.006

Therefore, 0.06 is 10 times as much as 0.006


3 0
3 years ago
Read 2 more answers
PLSS HELP ASAP!!! <br><br> Given: 2x−1=6x−17<br> Prove: x=4
AlekseyPX

Answer:

33232

Step-by-step explanation:

8 0
3 years ago
Ok this may be hard but I found this on my test ;--;
umka2103 [35]

Answer:

-2383.83870968

Step-by-step explanation:

I hope this is right...

8 0
3 years ago
PLSS ANSWER MY QUESTION
Taya2010 [7]

Answer:

1) Area of frame: 140cm^2 ; Area of picture: 40cm^2 ; Total Area: 180cm^2.      

2) Area 1 =  48cm^2 ; Area 2 = 12cm^2 ; total area = 60cm^2 [first answer line : 60cm^2]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as 140cm^{2} ; and the area of the photo should be written as 40cm^{2})

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as 180cm^2)

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as 48cm^{2} ; the area 2 should be written as 12cm^2)

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: 60cm^2)

The area of the figure is 60cm^2

8 0
2 years ago
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
3 years ago
Read 2 more answers
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