Answer:
a) L(x,y,z) = (-4,0,2)+(2,8,-7)*t
b) (2-z)/7= y/8=(x+4)/2 (option B)
Step-by-step explanation:
the parametric equation of the line passing through the point P₀= (-4,0,2) and parallel to the vector v=2i + 8j - 7k is
L(x,y,z)=P₀+v*t
therefore
L(x,y,z) = (-4,0,2)+(2,8,-7)*t
or
x=x₀+vx*t = -4 + 2*t
y=y₀+vy*t = 8*t
z=z₀+vz*t = 2 -7*t
solving for t in the 3 equations we get the symmetric equation of the line:
(2-z)/7= y/8=(x+4)/2
thus the option B is correct
