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Vinil7 [7]
4 years ago
14

PLEASE HURRY 9x^2 + 64 = 0 I NEED THE WORK SHOWN IN ORDER TO GET CREDIT

Mathematics
2 answers:
seropon [69]4 years ago
6 0

Answer:

x = ± \frac{8}{3} i

Step-by-step explanation:

subtract 64 from both sides

9x² = - 64 ( divide both sides by 9 )

x² = - \frac{64}{9} ( take the square root of both sides )

x = ± \sqrt{-64/9} = ± \frac{8}{3} i


Mars2501 [29]4 years ago
6 0

Answer:

see below

Step-by-step explanation:

9x^2 + 64 = 0

9x^2 = -64

x^2 = -64 / 9  

Taking square roots of both sides:-

x = +/-  (-8/3)

x = -8i/3 , 8i/3

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