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podryga [215]
3 years ago
7

The base of a solid SSS is the region bounded by the ellipse 4x^2+9y^2=364x 2 +9y 2 =364, x, squared, plus, 9, y, squared, equal

s, 36. Cross-sections perpendicular to the yyy-axis are equilateral triangles. Determine the exact volume of solid SSS.
Mathematics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

4π

Step-by-step explanation:

4x² + 9y² = 36

Divide all  through by 9

4/9x² + ²y² = 44

\int\limits^3_0 {\pi y^{2} } \, dx

\int\limits^3_0 {4-\frac{4}{9} }x^{2}  \, dx

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