Answer:
The value of Mary's investment after two years = £12362.7
Step-by-step explanation:
P = Principal / initial amount
R = rate of interest per cent per year
T = number of years
A = final amount at the end of T years
Then:
A = P*(1 + R/100)^2
In our example:
P = £12000
R = 1.5 per cent per year
T = 2 years
Thus:
A = 12000*(1 + 1.5/100)^2
= 12000*(1 + 0.015)^2
= 12000*(1.015)^2
= 12000*(1.030225)
= 12362.7
Value of investment after two years = £12362.7
I think Theodosius the best measure. The outliers will not effect the measure. If you use mean, you add all the data points and divide by the number of data points. The extremes will skew the data. If you use mode, that may work also. You find the data that occurs most often.
Answer:
Step-by-step explanation:
f(x) = 1.8x is a linear function and does not model the growth of bacteria. Perhaps you meant f(x) = 1.8^x, which is an exponential function whose initial value is 1. Please ensure that you have copied down this problem exactly as it was presented.
I Think the awnser would be 9,jsdfgeuriyftveywoqtfryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
The significant figures of 6.07 are 3 significant figures.