P(> or =70) =0.65
P(Collins inside) =0.80
P(not 70) = 1-P(70) =>0.35
P(Collins inside) = 0.1
Then P(70 AND Collin inside) .65 x .8 =0.52
P( not 70 AND Collin Outside = 0.35 x 0.1=0.035
TOTAL Possibility [(70 AND Inside) OR (not 70 AND Outside):
=0.52 + 0.034 =0.555
Answer:
the woman has to live 1 mile from work to minimize the expenses
Step-by-step explanation:
Given the data in the question;
the distance within 9 miles ⇒ 0 < x > 9
Total costs Q = cx + 4c/( x + 1)
costs should be minimum ⇒ dQ/dx = 0
⇒ d/dx [ cx + 4c/( x + 1) ] = 0
⇒ ( x + 1)² = 4
take square root of both side
√[ ( x + 1)² ] = √4
x + 1 = 2
x = 2 - 1
x = 1
Therefore, the woman has to live 1 mile from work to minimize the expenses
Answer:
x = 10.52 m
Step-by-step explanation:
Given that,
Length of a park = 90 m
Width of a park = 60 m
Area, A = 9000 m²
A uniform strip borders all four sides of the park for parking. We need to find the width of the strip. Let it is x. Now the area becomes,
(90+2x)(60+2x) = 9000
So, the width of the strip is equal to 10.52 m.
Answer:
≈ 0.2526
Step-by-step explanation:
<u>The number of combinations of 4 out of 8:</u>
- 8C4 = 8!/(4!(8-4)!)= 8*7*6*5/(1*2*3*4)= 70
<u>Success factor is: </u>
<u>and failure factor is: </u>
<u>Probability:</u>
