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ziro4ka [17]
3 years ago
8

Plz help me with 7-12 I really need it asap

Mathematics
1 answer:
lukranit [14]3 years ago
6 0
There is number 12 that’s the only one I’m going to do

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Melissa makes necklaces and sells them online. She charges $88 per necklace. Her monthly expenses are $3,745. How many necklaces
Dovator [93]
She will need to sell 18 necklaces a month to reach 1650
4 0
4 years ago
Read 2 more answers
The park is 400 feet. The length of the park is 50longer than the width . what is the length of the park
Kipish [7]

Answer: 125 ft.

Step-by-step explanation:

Assuming the perimeter of the park is 400 ft, the equation can be represented as

2l + 2w = 400

Since we know that the width is 50 ft shorter than the length, using algebra, you replace the variable w, with

2l + 2(l-50) = 400

Then, solve for variable l, or length

2l +2l - 100 = 400

4l = 500

l = 125

Now, plug in l and solve for w

2(125) + 2w = 400

250 + 2w = 400

2w = 150

w = 75

2(125) + 2(75) = 400

250+150 = 400

400=400

l = 125, w = 75

So the length is 125 ft

6 0
3 years ago
Read 2 more answers
1. Delia brushes her teeth 1/6 hour each day.
Roman55 [17]

Answer:

PART A: 28 hours, PART B: 16800 minutes

Step-by-step explanation:

Delia Brushes her teeth =  1/6 hour

PART A

Total Week= 1 week

Total number of  days in a week= 7 days

Total number of hours in a day= 24 hours

Total number of hours in a week= 24× 7 hours

Total number of hours in a  week=  168 hours

Number of hours that Delia brushes her teeth = \frac{1}{6} × 168 hours

Number of hours that Delia brushes her teeth = 28 hours

Hence, the correct answer is 28 hours

PART B

Total number of  days in a week= 7 days

Total number of hours in a  week=  168 hours

Total number of minutes in a  week=  168 × 60

Total number of hours in a  week=  100800 Minutes

Number of minutes that Delia brushes her teeth = \frac{1}{6}× 100800

Number of hours that Delia brushes her teeth = 16800 minutes

Hence, the correct answer is 16800 minutes

4 0
3 years ago
A credit reporting agency claims that the mean credit card debt in a town is greater than $3500. A random sample of the credit c
Lera25 [3.4K]

Answer:

Claim is false

Step-by-step explanation:

Claim : A credit reporting agency claims that the mean credit card debt in a town is greater than $3500.

H_0:\mu \leq 3500\\H_a:\mu = 3500

n = 20

Since n <30

So we will use t test

Formula : t =\frac{x-\mu}{\frac{s}{\sqrt{n}}}

s = standard deviation = 391

x = 3600

n = 20

t =\frac{3600-3500}{\frac{391}{\sqrt{20}}}

t =1.14

Degree of freedom = n-1 = 20-1 = 19

α=0.10

So, using t table

t_({\frac{\alpha}{2},d.f.}) = 1.72

t critical > t calculated

So we accept the null hypothesis

Hence we reject the claim that the mean credit card debt in a town is greater than $3500.

7 0
3 years ago
Help with question 8 a and b)
Artist 52 [7]
I think when you subtract 4 from x, you are shifting the graph right horizontally 4 units.  When you add 84 at the end of the function, you are shifting it up vertically 84 units.  When you times it by -5, you are stretching it by a factor of 5 and flipping it upside down.

just think of how each term effects the y value.  
5 0
3 years ago
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