1. Delia brushes her teeth 1/6 hour each day.
1 answer:
Answer:
PART A: 28 hours, PART B: 16800 minutes
Step-by-step explanation:
Delia Brushes her teeth = 1/6 hour
PART A
Total Week= 1 week
Total number of days in a week= 7 days
Total number of hours in a day= 24 hours
Total number of hours in a week= 24× 7 hours
Total number of hours in a week= 168 hours
Number of hours that Delia brushes her teeth = × 168 hours
Number of hours that Delia brushes her teeth = 28 hours
Hence, the correct answer is 28 hours
PART B
Total number of days in a week= 7 days
Total number of hours in a week= 168 hours
Total number of minutes in a week= 168 × 60
Total number of hours in a week= 100800 Minutes
Number of minutes that Delia brushes her teeth = × 100800
Number of hours that Delia brushes her teeth = 16800 minutes
Hence, the correct answer is 16800 minutes
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Answer:
The answer to your question is below
Step-by-step explanation:
See the graph below
Process
1.- Find the distance from A to B, B to C, C to D, A to D
Formula
d =
d AB =
dBC =
dCD =
dAD =
2.- Find the perimeter
Perimeter = 2 =
u
3.- Find the area
Area =
Area =
Answer:
Height of mound = 794 ft
Step-by-step explanation:
To illustrate the angle of elevation and distance, i have drawn it and attached below.
Now, from my diagram;
h = the height of the mound
At his first point of his trip to the foot of the mound, the angle of elevation is 40°, while the horizontal distance to the foot of the mound is "X"
So, by triangle definition,
tan(40°) = h/x
And so;
h = x tan40
h = 0.8391x - - - - (eq 1)
At his second point of the trip to the foot of the mound, Joe is now,
"(x - 450) ft" from the foot of the mound.
Thus, his angle of elevation is 40 + 18 = 58°.
So, by triangle definition,
tan(58°) = h/(x - 450)
h = (x - 450)•(tan(58°))
h = 1.6003(x - 450)
h = 1.6003x - 720.135 - - - - -(eq2)
To get the height(h) of the mound, let's equate (eq1) to (eq2).
0.8391x = 1.6003x - 720.135
1.6003x - 0.8391x = 720.135
0.7612x = 720.135
x = 720.135/0.7612
x = 946.0523 ft
Let's put this value for x in eq (1);
h = 0.8391 x 946.0523 = 793.83 ft ≈ 794ft
