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3 years ago

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(1 pt) Which answer is the same as moving the decimal in 6.73 three places to the left? A. dividing 6.73 by 103 B. dividing 6.73

by 102 C. multiplying 6.73 by 100 D. multiplying 6.73 by 1,000

1 answer:

slava [35]3 years ago

5 0

It would be a
A. 6.73 / 10^3
Moving it to the left would make it 0.00673

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Answer:

Statement A - True.

Statement B - False.

Statement C - True.

Statement D - False.

Step-by-step explanation:

(a) A sequence is convergent if and only if all of its subsequences are convergent - this statement is correct.

(b) A sequence is bounded if and only if all of its subsequences are bounded - this statement is incorrect.

(c) A sequence is monotonic if and only if all of its subsequences are monotonic - this statement is correct.

(d) A sequence is divergent if and only if all of its subsequences are divergent - this statement is incorrect.

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Round this number to nearest 10,000. 4,278,003

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To Round of the number given, first you have to find the ten thousands place on the given number. Started from ones, tens, hundreds, and moving on, the number in the ten thousands place would be 7 in your case.

Now, looking to the number on the right of 7 which is 8, it is bigger than 5, and therefore, we round up 7 and let 8 go to zero.

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Could someone please help me:) I am stick and I am not sure what to do

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Answer:

Part 5.1.1:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

We are given that:

$\displaystyle \sin 2A = \frac{\sqrt{15}}{8}$

Part 5.1.1

Recall that:

$\displaystyle \sin^2 \theta + \cos^2 \theta = 1$

Let θ = 2<em>A</em>. Hence:

$\displaystyle \sin ^2 2A + \cos ^2 2A = 1$

Square the original equation:

$\displaystyle \sin^2 2A = \frac{15}{64}$

Hence:

$\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1$

Subtract:

$\displaystyle \cos ^2 2A = \frac{49}{64}$

Take the square root of both sides:

$\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}$

Since 0° ≤ 2<em>A</em> ≤ 90°, cos(2<em>A</em>) must be positive. Hence:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2

Recall that:

$\displaystyle \begin{aligned} \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &= 1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}$

We can use the third form. Substitute:

$\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1$

Solve for cosine:

$\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}$

In conclusion:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

(Note that since 0° ≤ 2<em>A</em> ≤ 90°, 0° ≤ <em>A</em> ≤ 45°. Hence, cos(<em>A</em>) must be positive.)

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