So, We Have A Rate That We Need To Simplify. We Have:
88 students for every 4 classes
So, We Need To Simplify This Rate. In Order To Do This, We Need To Change Is To A Fraction. It Is:
88 students
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4 classes
Now, We Have To Simplify. We Can Do That By Remembering How To Simplify Fractions.
So,
88 ÷ 2 = 44 ÷ 2 = 22 students
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4 ÷ 2 = 2 ÷ 2 = 1
So, The Unit Rate For 88 Students For 4 Classes Is:
22 Students For One Class
Answer:
Step-by-step explanation:
To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:
And the vector B is formed with the solution of each equation of the system:
To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called .
The value of y using Cramer's rule is:
Find the value of the determinant of each matrix, and divide:
Answer: (141.1, 156.48)
Step-by-step explanation:
Given sample statistics :
a) We know that the best point estimate of the population mean is the sample mean.
Therefore, the best point estimate of the mean weight of all women =
b) The confidence interval for the population mean is given by :-
, where E is the margin of error.
Formula for Margin of error :-
Given : Significance level :
Critical value :
Margin of error :
Now, the 90% confidence interval for the population mean will be :-
Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)
C) x = -19/10 because when solving it with substitution u get x=-19/10 & y=153/10
Answer:
i) superset (A)
ii) 0.577 (A)
Step-by-step explanation:
i) A subset is a set which has all its elements contained in another set.
For two sets A and B, if each element of set A is an element of set B, then A is a subset of B.
A superset is a set that houses another set. So if set A is a subset of set B, then B is a superset of A.
Proper subset
For a set (A) to be a proper subset of another (B) every element of A would be in B but there exists at least one element in B that is not in A.
An Empty Set (or Null Set) doesn't have aren't any elements in it. It is empty.
Since every element of the superset is in the superset. Therefore, A superset contains all the subset of superset.
ii) Square root of 1/3 = √⅓
= ± √⅓ = +√⅓ or -√⅓
+√⅓ = +(√1/√3) = +(1/√3)
+√⅓ = +(1/1.7321)
+√⅓ = +0.577
Therefore Positive square root of 1/3 is 0.577 (A)