All categories

3 years ago

How many times does 7 go into 19

Mathematics

1 answer:

Svetllana [295]3 years ago

6 0

7 goes into 19 2 complete times. 7*2=14, but 7*3=21

the true answer is a decimal, one around 2.71

You might be interested in

Find the LCM of the polynomials.<br> x² - x - 42<br> x2 + x - 56

den301095 [7]

Answer:

x^3+7x^2-50x-336 or (x-7)(x+6)(x+8)

Step-by-step explanation:

Factor each equation.

x^2-x-42= (x-7)(x+6)

x^2+x-56= (x-7)(x+8)

The common factor is (x-7), therefore the other factors of the expressions must multiply to find the common factor.

(x-7)(x+6)(x+8)=x^3+7x^2-50x-336.

7 0

3 years ago

Maths plz help me soon xD

LUCKY_DIMON [66]

rationalise the denominator by multiplying both top and bottom by (8-5√3) then expand and simplify

7 0

3 years ago

Evaluate the function f(x)= x^2 + 6x for the given value of x. Simplify your answer.

Anit [1.1K]

Step-by-step explanation:

$f\left(x^2+6x+h\right)$

$=fx^2+f\cdot \:6x+fh$

$=fx^2+6fx+fh$

8 0

3 years ago

Suppose that the regression equation y = 16.99 + 0.32 x1 + 0.41 x2 + 5.31 x3 predicts an adult’s height (y) given the individual

umka21 [38]

Answer:

Step-by-step explanation:

It is given that the regression equation

$y = 16.99 + 0.32 x_1 + 0.41 x_2 + 5.31 x_3$

predicts an adult’s height (y) given the individual’s mother’s height (x1), his or her father’s height (x2), and whether the individual is male (x3 = 1) or female (x3 = 0).

The coefficient of x1 = 0.32 represents the increase in height of the child due to one inch increase in mother.

Similarly coefficient of x2 = 0.42 represents the increase in height of the child due to one inch increase in father.

and coefficient of x3 = 5.31 represents the increase in height of the child due to being a male than a female.

8 0

3 years ago

Breyers is a major producer of ice cream and would like to test the hypothesis that the average American consumes more than 17 o

zhenek [66]

Answer:

The p-value would be 0.0939

Step-by-step explanation:

We can set a standard t-test for the Null Hypothesis that $H_0: 18.2\geq 17$

The test statistic then takes the form

$t=\frac{18.2-17}{3.9/\sqrt{15}}=1.317$

with this value we then can calculate the probability that is left to the right of this value $P(X>1.317)$ . From theory we know that t follows a standard normal distribution. Then $P(X>1.317)=0.0939$ which is smaller than the p-value set by Breyers of 0.10

3 0

3 years ago