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Arlecino [84]
3 years ago
15

A positive number with divisors besides one and itself is called ?

Mathematics
2 answers:
Bezzdna [24]3 years ago
8 0

We know that a positive number where only one and itself divide it is called a prime number. A positive number with divisors other than 1 and itself are called composite numbers.

Fiesta28 [93]3 years ago
4 0

Answer:

The answer is: A positive number with divisors besides one and itself is called a <em>composite number.</em>

Step-by-step explanation:

Unlike prime numbers, which can only be divided by one and themselves, composite numbers have other divisors apart from these two. All even numbers greater than two, for example, are composite numbers because of the fact that they can all be divided by one, themselves and the number two.

<em>An example of a prime number is 11 (It can only be divided by 11 and 1)</em>

<em>An example of a composite numbers is 12 (It can be divided by 1, 2, 3, 4, 6 and 12) </em>

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The answer is
\frac{-6i-3}{5}.

Before we rationalize the denominator, we must simplify the numerator and denominator.  We evaluate the square root on the top, and combine like terms on the bottom:
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To rationalize the denominator, we multiply by the conjugate.  The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign.  The conjugate of -2-i is -2+i:

\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}&#10;\\&#10;\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}&#10;\\&#10;\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}&#10;\\&#10;\\=\frac{-6i+3i^2}{4-2i+2i-i^2}&#10;\\&#10;\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}
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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

2(2x-1)=3

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4 0
3 years ago
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