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Arlecino [84]
3 years ago
15

A positive number with divisors besides one and itself is called ?

Mathematics
2 answers:
Bezzdna [24]3 years ago
8 0

We know that a positive number where only one and itself divide it is called a prime number. A positive number with divisors other than 1 and itself are called composite numbers.

Fiesta28 [93]3 years ago
4 0

Answer:

The answer is: A positive number with divisors besides one and itself is called a <em>composite number.</em>

Step-by-step explanation:

Unlike prime numbers, which can only be divided by one and themselves, composite numbers have other divisors apart from these two. All even numbers greater than two, for example, are composite numbers because of the fact that they can all be divided by one, themselves and the number two.

<em>An example of a prime number is 11 (It can only be divided by 11 and 1)</em>

<em>An example of a composite numbers is 12 (It can be divided by 1, 2, 3, 4, 6 and 12) </em>

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7 0
3 years ago
Simplify (3x - 2) - (3x + 6)
Naddika [18.5K]
(3x - 2) - (3x+ 6)=


3x - 5) + (3x + 6)

3x - 5 + 3x + 6

Combine the 'x'-terms: 3x + 3x = 6x
Combine the numbers: -5 + 6 = 1

The expression is equivalent to . . . . . 6x + 1
5 0
2 years ago
What is a polynomial function in standard form with zeroes 0, 1, 4, and –1?
mr Goodwill [35]
The polynomial for this case is given by:
 (x) * (x-1) * (x + 1) * (x-4) = 0
 Rescribing we have:
 (x) * (x ^ 2-1) * (x-4) = 0
 (x) * (x ^ 3 - 4x ^ 2 - x + 4) = 0
 (x ^ 4 - 4x ^ 3 - x ^ 2 + 4x) = 0
 Therefore, the polynomial in standard form is:
 f (x) = x ^ 4 - 4x ^ 3 - x ^ 2 + 4x
 Answer:
 
a polynomial function in standard form with zeroes 0, 1, 4, and -1 is:
 
f (x) = x ^ 4 - 4x ^ 3 - x ^ 2 + 4x
3 0
3 years ago
Solve the problem given below
vladimir1956 [14]

<u>Answer</u>

<em>12 in by 12 in</em>

<u>Explanation</u>

The original length = x

This makes the length of the cube made to be = x - (2×2)

                                                                               = (x - 4) in

height of the cube = 2 in

Volume of the cube = (x - 4) × (x - 4) × 2 = 128

                                 = (x² - 8x + 16) × 2 = 128

                                = 2x² - 16x + 32 = 128

                                 = 2x² - 16x + 32- 128=0

                                 = 2x² - 16x - 96 = 0

                                 = x² - 8x - 48 = 0

lets use the factor method to solve the quadrilatic equation above,

x² - 8x - 48 = 0

proctuct = -48

sum = -8

The two factors are; -12 and 8.

(x + 8)(x - 12) = 0

So the value of x are 12 and -8.  Since x is a length, it can not be negative.

∴ x = 12 in.

The original dimensions of the sheet are <em>12 in by 12 in</em>.

7 0
3 years ago
Read 2 more answers
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