The situation is represented by a drawing with a right triangle where an airplane is at the top corner, the elevation angle (opposite to the airplane) is 70°, the height (vertical leg) is x, and the adjacent leg (horizontal leg) to the 70° angle is 800.
Then, to find the height x, which is the opposite leg to the angle, you can use the tangent ratio, which is opposite leg divided by adjacent leg:
tan(x) = opposite leg / adjacent leg => tan(70°) = x / 800
Answer: tan(70°) = x / 800
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
The answer of this problem will be 622 because you round that eight to the one and get your answer
Hey there!☺
Add the fraction together.
Let's simplify 43/15.
Hope this helps!
I think the answer is, r= C/2<span>π</span>
