We want to know when we brought it back in to the room. at that time
the temperature difference is 80 - 42 = 38 so we have to solve
<span>
38=9<span>e<span>^−.3344t</span></span></span> for t
this time we get
<span><span>38 / 9</span>=<span>e^<span>−.3344t</span></span></span>
<span>t=<span><span>ln(<span>38 / 9</span>)</span><span> / −.3344</span></span></span>
<span>t=−4.3</span>
so 4.3 minutes before 2:10
Answer:
the first one
Step-by-step explanation:
the answer is the first one
Answer:
-20.50?
Step-by-step explanation:
I think you said he added 5 dollars in his account which would get some of his debt removed. But he would still have a remaining -20.50 dollars to get rid of.
Answer:
length, width, and height are (b+2), (b-2), (b+3)
Step-by-step explanation:
Doing what the problem statement tells you to do, you get ...
(b^3 +3b^2) -(4b +12)
= b^2(b +3) -4(b +3) . . . . . factor each pair of terms
= (b^2 -4)(b +3) . . . . . . . . . write as a product
= (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares
The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.
Step-by-step explanation:
