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Marysya12 [62]
2 years ago
14

What is the range of the graph

Mathematics
1 answer:
sammy [17]2 years ago
4 0

Answer: The range is [3, infinity).

Step-by-step explanation: The "[" means that it is apart of the graph. The ")" means it is not apart of the graph.

The graph's range (which is it's highest lowest to highest y-value), the lowest is 3 on the y axis, and then stems on to infinity. The reason why infinity is not apart of the graph is because it has no end and infinity is not a number.

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Artyom0805 [142]

Answer:

The answer is 16x + 7

Step-by-step explanation:

First you want to add all of the like terms.

(8x + 10 + 12x + 7) - (4x+10)

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Now you want to subtract all of the like terms

16x + 7

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The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume
k0ka [10]

Answer: between 56.45% and 57.55%


Explanation:


We are given:

μ = population mean = 57%

σ = population standard deviation = 3.50%

n = sample size = 40

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We need to calculate the confidence interval in which we should find the sample mean \bar{x}.


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s = 0.55

Now, there are two equivalent ways to arrive to the answer:


<u>1) short way: use the Empirical Rule</u>, also known as 68–95–99.7 Rule, to remember that 68% of the data lies within 1 standard deviation from the mean.


Therefore, the confidence interval should be:

\mu - 1 s \leq \bar{x} \leq \mu + 1 s

57 - 0.55 ≤ \bar{x} ≤ 57 + 0.55

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<u>2) long way: make all the calculations</u>.

First, find the critical value corresponding to the confidence level required:

1 - \frac{\alpha }{2} = 1 - \frac{1 - CL}{2} = 1 - \frac{1 - 0.68}{2} = 0.84


Now, since the sample size is greater than 30 and it is said to be statistical significant, we can use a z-score table (instead of a t-score table).

Looking for which z-score corresponds to a probability closest to 0.84, we get z = 1.00 (which confirms the Empirical Rule).


Now, we can find the confidence interval requested:

\mu - z \cdot s \leq \bar{x} \leq \mu + z \cdot s

57 - 1·0.55 ≤ \bar{x} ≤ 57 + 1·0.55

56.45 ≤ \bar{x} ≤ 57.55

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3 years ago
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