In the drawing below , PQ is parallel to ST. Triangle is similar to triangle TSR.

Divide. Enter the answer in simplest form.<br> 6 2/3 divided by 2 1/2

Roman55 [17]

I can answer but ur not being specific it what is the 6 for and what is the 2 for because there’s a space

8 0

2 years ago

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Distance between (-3,1) (1,5)

Mamont248 [21]

Answer & Step-by-step explanation:

For this problem, we will use the distance formula.

$d=\sqrt{(x2-x1)^2+(y2-y1)^2}$

For our (x1, y1), we will use (-3, 1). For our (x2, y2), we will use (1, 5). Now let's plug in our numbers and solve the problem.

$d=\sqrt{(1-(-3))^2+(5-1)^2}$

$d=\sqrt{4^2+4^2}$

$d=\sqrt{16 + 16}$

$d=\sqrt{32}$

$d=5.657$

So, the distance between (-3,1) and (1,5) is 5.657 units.

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al

Furkat [3]

Answer: $\frac{\sqrt[4]{10xy^3}}{2y}$

where y is positive.

The 2y in the denominator is not inside the fourth root

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Work Shown:

$\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\$

The idea is to get something of the form $a^4$ in the denominator. In this case, $a = 2y$

To be able to reach the $16y^4$ , your teacher gave the hint to multiply top and bottom by $2y^3$

For more examples, search out "rationalizing the denominator".

Keep in mind that $\sqrt[4]{(2y)^4} = 2y$ only works if y isn't negative.

If y could be negative, then we'd have to say $\sqrt[4]{(2y)^4} = |2y|$ . The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0

2 years ago

You deposit $400 into an account that pays 2% annual interest compounded quarterly.

jeka57 [31]

A.

A = 400 (1 + (0.02)/4)^4t where t = number of years and A = amount after t years
simplifying that becomes

A = 400 (1.005)^4t

b amount after 5 years is

400 (1.005)^(4*5) = 400 (1.005)^20 = $ 441.96

4 0

3 years ago

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Help please! Will give brainly! Explain how the equation y=x^2 differs from the equation y=x

ira [324]

Answer:

Below.

Step-by-step explanation:

$y=x^2$ is also $y = x*x$