Answer:
x=30o+n90on∈Z
Step-by-step explanation:
cos2x=sin(90o−2x)=sin(2x−30o)
Which mean 90o−2x=2x−30o+n360o
or 90o−2x+2x−30o=(2n+1)180o
The later cannot be true.
so x=30o+n90on∈Z
Answer: -4
Step-by-step explanation:
Solve 2x+7=-1
2x. =-8
x. =-4
Yshejrhhe is they easiest of them all and as you can see I just can’t fail it bro ik too smart yk it’s y>-3x +1-5
Before we can make sure that E is correct, we need to make the denominator is equal with questions and the choices or convert into decimal.
2/3 = 0.66
1/3=0.33
1/5=0.2
2/6=1/3 = 0.33
1/2 = 0.5
7/10 = 0.7
7/9 = 0.77
The question is :
2/3 < x < 7/9
0.66 < x < 0.77
We need to divide into 2 parts :
0.66 < x
x < 0.77
So we need to find the answer that x is greater that 0.66 and we got 7/10. And 7/10 is less than 7/9.
Hope this helps. Please ask if you don't understand.
Answer:
PART A: Inequality (a)
Solve for y
The graph of y ≥ ⅓(8-x) is represented by the upper red line and all points in the shaded area below it. The line is solid because points on the line satisfy the conditions.
Inequality (b)
Solve for y
The graph of y ≥ 2 - x is represented by the lower blue line and all points in the shaded area above it. The line is solid because points on the line satisfy the conditions. The solution lies in the purple area. It consists of all combinations of x and y that make y ≥ ⅓(8 - x) and y ≥ 2 - x. A practical but not a mathematical condition is that all values of x and y must be zero or positive numbers (for example, you can't have -2 servings of food), so I have plotted only the numbers in the first quadrant.
PART B: If a point is a solution of the system, then the point must satisfy both inequalities of the system.
For x=8, y=2. Verify inequality A is not true. So the point does not satisfy inequality A. Therefore, the point is not included in the solution area for the system.
PART C: I choose the point (3,1) which is included in the solution area for the system.
That means Michelle buys 3 serves of dry food and 1 serving of wet food.
Step-by-step explanation:
Plz mark Brainliest?
