All categories

3 years ago

Q8 Q10.) Solve the given system of equations.

Mathematics

2 answers:

Yuliya22 [10]3 years ago

5 0

Answer is A!

x + 5 + 3(1) = 9
x + 5 + 3 = 9
x + 8 = 9
x = 9 - 8
x = 1

Final answers: x = 1, y = 5, z = 1 or (1, 5, 1)

Scorpion4ik [409]3 years ago

3 0

See the attached picture:

only one solution (1,5,1)

You might be interested in

What is the correct answer?

Nutka1998 [239]

Answer:

D) 8

Step-by-step explanation:

You multiply 10 by 12 to get 120 so you multiply x by 12 to get 96.

96 = 12x

/12 /12

8 = x

5 0

3 years ago

QUICK, BRAINLIEST FOR 1ST ANSWER. 14.5 is incorrect!

ra1l [238]

To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by

1/12.5 = 0.08, or 8%

We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.

4 0

3 years ago

Ethan drove 100 miles and used 4 gallons of gasoline. Abby drove 225 miles and used 10 gallons of gasoline. Who got better gas m

olchik [2.2K]

Answer:

Ethan

Step-by-step explanation:

Divide the miles by the gallons of gas

8 0

4 years ago

Read 2 more answers

2nd question this is still confusing even after getting the formula

Nana76 [90]

Check the picture below.

so the figure is really just 3 rectangles and two triangles.

simply get the area of all 5, sum them up, and that's the area of the figure.

recall that area of a triangle A = ½bh.

3 0

3 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

x = 2
y = -1

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

3 years ago