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2 years ago

What is 0.86/5-0.3*0.5

Mathematics

2 answers:

klio [65]2 years ago

7 0

0.86/5=0.172
0.3×0.5=0.15
0.172_0.15=0.022

grigory [225]2 years ago

5 0

0.86/5-0.3*0.5= 2 answers

1. can be 11/500

2. it can be 0.022 but im positive it has to be 11/500

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ki77a [65]

Answer:

Step-by-step explanation:

(f O g) this basically means that the input x first goes trough the function g and then f. Like f(g(x)).

So when x went trough g, you got the output g(x) and then this went trough f and you got f(g(x)) = -8 = 'f(x)'.

With this in mind you can retrace your steps by first looking at what input can get -8 as an output, for f this is -4. this means g(x) = -4

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2 years ago

One number i ix le than a econd number. Four time the firt i 2 more than 6 time the econd. Find the number

Kruka [31]

When the difference between one and two numbers is two, the two numbers are -10 and -12.

Given that,

The difference between one and two numbers is two. Twelve more than six times the second is four times the first.

We have to find the number.

We know that,

The system of equation we get

x=y-2 ----->equation(1)

4x=12+6y ----->equation(2)

Substitute for x in the equation(2)

4(y-2)=12+6y

4y-8=12+6y

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Substitute y=-10 in equation(1)

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Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.

To learn more about number visit: brainly.com/question/17429689

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11 months ago

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IgorC [24]

2S/7 2 shaded out of 7 circles

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3 years ago

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Kipish [7]

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Step-by-step explanation:

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3 years ago

A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s

Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

Let $\hat p$ = proportion of students who felt comfortable reporting cheating by their fellow students

Now, point estimate ( $\hat p$ ) is calculated as;

$\hat p=\frac{X}{n}$

where, X = number of students who answered yes = 1,344

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3 years ago