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Anuta_ua [19.1K]
3 years ago
7

A message center receives calls from 6 p.m. until 6 a.m. Typically, 50% of the calls come in between 6 p.m. and 9 p.m.; 25% of t

he calls come in between 9 p.m. and midnight; 20% of the calls come in between midnight and 3 a.m.; and 5% of the calls come in between 3 a.m. and 6 a.m.
What is the probability that a call will come in between 6 p.m. and midnight?

Question 5 options:

25%


50%


55%


75%
Mathematics
1 answer:
Leto [7]3 years ago
7 0
Midnight to 3 a.m.: 20%
3 a.m. to 6 a.m. 5%

Midnight to 6 a.m. = 20% + 5% = 25%
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A sport analyst wants to determine the mean salary of a Baseball player for 2015. He believes an estimate of this average salary
djyliett [7]

Answer:

<em>The large sample size 'n' =  199.6569≅ 200</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given Standard deviation of salary for all baseball players for 2015 is about $5,478,384.55

<em>Standard deviation of  of salary for all baseball players for 2015 </em>

<em>   (S.D ) σ =  $5,478,384.55</em>

Given estimate of this average salary for all baseball players for 2015

                          =  $497,000

<em>Given Margin of error of error is  =  $497,000 </em>

<em>Level of significance ∝ = 80% </em>

<em>The critical value Z₀.₂₀ = 1.282  </em>

<u><em>Step(ii):</em></u><em>-</em>

<em>Margin of error of error is  determined by</em>

<em>           </em>M.E = \frac{Z_{0.20} S.D}{\sqrt{n} }<em></em>

<em>          </em>497,000 = \frac{1.282 X 5,478,384.55}{\sqrt{n} }<em></em>

Cross multiplication , we get

 \sqrt{n}  = \frac{1.282 X 5,478,384.55}{497,000 }

On calculation , we get

√n = 14.13

<em>Squaring on both sides, we get</em>

n = 199.6569

<u><em>Conclusion</em></u><em>:-</em>

<em>The large sample size 'n' =  199.6569≅ 200</em>

<em>    </em>

<em></em>

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It would be A, because her annual premium rate is $3.25 for every $1,000. So 3.25x130=$422.50
4 0
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Answer:

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Step-by-step explanation:

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The value of y varies directly with x, and y = 18 when x = 12. find y when x = 132.
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